Only 1% students solved it (IAS exam)

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Only 1% Students solved it (IAS exam)
Solve this
3+5+6=151872
5+5+6=253094
5+6+7=303585
5+5+3=251573
then
9+4+7=_______?
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The solution to the first 4 digits is pretty straight forward, and I am sure most of you must have easily got it.

It works out to be a+b+c = (a*b)(a*c)??

The last 2 digits are really tough to crack…

Here’s how you do it.

The last 2 digit is equal to reverse of the answer of (a*b)+(a*c)-b

If we test this formula for the first equation i.e. 3 + 5 + 6 = 151872

(axb) = (3x5) = 15;
(axc) = (3x6) = 18;
(a*b)+(a*c)-b = (3×5)+(3×6)-6 = 15 + 18 - 6 = 27 whos reverse is 72

Similarly this equation will fit all other equations in the sequence.

To find 9 + 4 + 7 = ??????
We use the same formula;
(axb) = (9x4) = 36;
(axc) = (9x7) = 63;
(a*b)+(a*c)-b = (9x4)+(9x7)-7 = 36 + 63 – 7 = 92 whos reverse is 29

Hence 9 + 4 + 7 = 366329